The sum of total number of carbonyl groups ( >C=O ) present in the major products X and Y in the following reactions is . [figure]
Answer
4
Solution
[figure] [-2CO2]heat [figure]
Both –COOH groups are β to the keto C=O (β-keto acid), so both are lost as CO2 through a cyclic six-membered transition state. X = pentan-3-one: 1 C=O.
[figure] [-H2O]heat [figure]
Here the –COOH groups are γ to the ring C=O, so there is no decarboxylation. They are cis-1,2, so they lose H2O to form a fused five-membered cyclic anhydride. Y: 2 (anhydride) + 1 (ketone) = 3 C=O.
Total = 1 + 3 = 4
Answer: 4