Initial pressure and volume of a monoatomic ideal gas are P and V. The change in internal energy of this gas in adiabatic expansion to volume Vfinal=27V is J.
- -2PV (3 3-1 )
- 43PV
- - 43PV
- 34PV
Answer
(3) - 43PV
Solution
Monoatomic gas: = 53, CV= 32R
Adiabatic: TV -1= constant Tf=T ( V27V )2/3= T9
U=nCV(Tf-T)= 32nRT ( 19-1 )
= 32PV (- 89 ) ( nRT=PV)
=- 43PV
Answer: (3)