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Thermodynamics (Physics) · Question 3

JEE Main 2026 (Online) 6th April Morning ShiftNumericalMedium📈 Topic in 52% papers+4
1

A certain gas is isothermally compressed to ( 13 )rd of its initial volume (V0=3 litre) by applying required pressure. If the bulk modulus of the gas is 3 105 N/m2, the magnitude of work done on the gas is J.

Answer

989

Solution

Isothermal process: PV= constant ⇒ P dV+V dP=0

⇒ B=-V dPdV=P

∴ Initial pressure P0=B=3 105 N/m2, V0=3 litre =3 10-3 m3

Work done on the gas in isothermal compression to V03:

W=P0V0 V0V=P0V0 3

=3 105 3 10-3 1.0986

=900 1.0986=988.7 J 989 J

Answer: 989

JEE Main 2026 (Online) 6th April Morning Shift

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2

A cylinder with adiabatic walls is closed at both ends and is divided into two compartments by a frictionless adiabatic piston. Ideal gas is filled in both (left and right) the compartments at same P, V, T. Heating is started from left side until pressure changes to 27P8. If initial volume of each compartment was 9 litres then the final volume in right-hand side compartment is litres. (for this ideal gas CP/CV=1.5)

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3

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4

An ideal gas undergoes a process maintaining relation between pressure (P) and volume (V) as P=P0 (1+ ( V0V )2 )-1, where P0 and V0 are constants. If two samples A and B (two moles each) with initial volumes V0 and 3V0 respectively undergo above mentioned process and attain same pressure, then the difference in the temperatures of these samples, TB-TA is . (R = gas constant)

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5

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6

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7

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8

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9

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11

10 mole of an ideal gas is undergoing the process shown in the figure. The heat involved in the process from P1 to P2 is Joule (P1 = 21.7 Pa and P2 = 30 Pa, Cv = 21 J/K mol, R = 8.3 J/mol K). The value of is . [figure]

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