RMgI when treated with ice cold water liberated a gas which occupied 1.4 dm3/g at STP. The gas produced is further reacted with iodine in presence of HIO3 to give compound (X). Compound (X) in presence of Na and dry ether produced compound (Y). Molar mass of compound (Y) is g mol-1. (Nearest integer)
Answer
30
Solution
RMgI + H2O → R–H + Mg(OH)I
1 g of gas occupies 1.4 dm3 at STP
⇒ molar mass = 22.41.4 = 16 g mol-1 ⇒ gas = CH4 (R = CH3)
Iodination (HIO3 removes HI and drives the reversible reaction forward):
CH4 + I2 CH3I + HI; 5HI + HIO3 3I2 + 3H2O ⇒ X = CH3I
Wurtz reaction: 2CH3I + 2Na dry ether CH3-CH3 + 2NaI ⇒ Y = ethane
Molar mass of Y = 2(12) + 6(1) = 30 g mol-1
Answer: 30