Classification of Elements and Periodicity in Properties · Question 10

The element expected to form largest ion to achieve the nearest noble gas configuration is

1. F
2. N
3. Na
4. O

The IUPAC name of an element with atomic number 119 is

1. ununennium
2. unnilennium
3. unununnium
4. ununoctium

The correct order of first ionization enthalpy for the given four elements is :

1. C < F < N < O
2. C < N < F < O
3. C < N < O < F
4. C < O < N < F

If first ionization enthalpies of elements X and Y are 419 kJ mol-1 and 590 kJ mol-1, respectively and second ionization enthalpies of X and Y are 3069 kJ mol-1 and 1145 kJ mol-1, respectively. Then correct statement is :

1. Both X and Y are alkaline earth metals
2. X is an alkali metal and Y is an alkaline earth metal
3. X is an alkaline earth metal and Y is an alkali metal
4. Both X and Y are alkali metals

Identify the incorrect match.

1. (b)-(ii)
2. (c)-(iii)
3. (d)-(iv)
4. (a)-(i)

Match the following : Which of the following is correct option?

1. (A)-(ii), (B)-(i), (C)-(iv), (D)-(iii)
2. (A)-(iii), (B)-(iv), (C)-(i), (D)-(ii)
3. (A)-(iv), (B)-(iii), (C)-(ii), (D)-(i)
4. (A)-(i), (B)-(ii), (C)-(iii), (D)-(iv)

For the second period elements the correct increasing order of first ionization enthalpy is :

1. Li < B < Be < C < N < O < F < Ne
2. Li < Be < B < C < O < N < F < Ne
3. Li < B < Be < C < O < N < F < Ne
4. Li < Be < B < C < N < O < F < Ne

The element Z = 114 has been discovered recently. It will belong to which of the following family/group and electronic configuration ?

1. Carbon family, [Rn] 5f14 6d10 7s2 7p2
2. Oxygen family, [Rn] 5f14 6d10 7s2 7p4
3. Nitrogen family, [Rn] 5f14 6d10 7s2 7p6
4. Halogen family, [Rn] 5f14 6d10 7s2 7p5

In which of the following options the order of arrangement does not agree with the variation of property indicated against it ?

1. I < Br < Cl < F (increasing electron gain enthalpy)
2. Li < Na < K < Rb (increasing metallic radius)
3. Al3+ < Mg2+ < Na+ < F- (increasing ionic size)
4. B < C < N < O (increasing first ionisation enthalpy)

The formation of the oxide ion, O2-(g) from oxygen atom requires first an exothermic and then an endothermic step as shown below: O(g) + e- O-(g); H = -141 kJ mol-1 O-(g) + e- O2-(g); H = +780 kJ mol-1 Thus, process of formation of O2- in gas phase is unfavourable even though O2- is isoelectronic with neon. It is due to the fact that,

1. O- ion has comparatively smaller size than oxygen atom
2. oxygen is more electronegative
3. addition of electron in oxygen results in larger size of the ion
4. electron repulsion outweighs the stability gained by achieving noble gas configuration.