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Integrals · Question 19

JEE Main 2026 (Online) 28th January Evening ShiftMCQMedium📈 Topic in 23% papers+4−1
1

Let f(x) = dxx2/3 + 2x1/2, be such that f(0) = -26 + 24 e(2). If f(1) = a + b e(3), where a, b Z, then a + b is equal to :

  1. -5
  2. -11
  3. -18
  4. -26

Answer

(2) -11

Solution

Put x = t6 dx = 6t5 dt, x2/3 = t4, x1/2 = t3

f = 6t5t4 + 2t3 dt = 6t2t + 2 dt = 6 (t - 2 + 4t + 2 )dt

= 3t2 - 12t + 24 e(t + 2) + C, where t = x1/6

f(0) = 24 e 2 + C = -26 + 24 e 2 C = -26

f(1): t = 1 f(1) = 3 - 12 + 24 e 3 - 26 = -35 + 24 e 3

a = -35, b = 24

a + b = -11

Answer: (2)

JEE Main 2026 (Online) 28th January Evening Shift

Keep practising — Integrals

2

Let [.] denote the greatest integer function. Then - 2 2 ( 12(3 + [x])3 + [ x] + [ x] ) dx is equal to :

  1. 12 + 5
  2. 11 + 2
  3. 15 + 4
  4. 13 + 1
JEE Main 2026 (Online) 28th January Evening Shift
3

Let f(t) = ( 1 - ( e t)1 - ( e t) ) dt, t > 1. If f (e /2 ) = -e /2 and f (e /4 ) = e /4, then equals

  1. 1 + 2
  2. -1 - 2 2
  3. -1 - 2
  4. -1 + 2
JEE Main 2026 (Online) 24th January Morning Shift
4

If f(x) satisfies the relation f(x) = ex + 01 (y + xex) f(y) dy, then e + f(0) is equal to .

JEE Main 2026 (Online) 24th January Evening Shift
5

Let f(x) = (2 - x2 ) ex ( 1 + x )(1 - x)3/2 dx. If f(0) = 0, then f ( 12 ) is equal to:

  1. 2e - 1
  2. 2e + 1
  3. 3e - 1
  4. 3e + 1
JEE Main 2026 (Online) 23rd January Morning Shift
6

The value of the integral 24 5 24 dx1 + [3] 2x is :

  1. 3
  2. 18
  3. 6
  4. 12
JEE Main 2026 (Online) 23rd January Morning Shift
7

Let I(x) = 3 dx(4x + 6) ( 4x2 + 8x + 3 ) and I(0) = 34 + 20. If I ( 12 ) = a 2b + c, where a, b, c N, (a, b) = 1, then a + b + c is equal to :

  1. 30
  2. 29
  3. 28
  4. 31
JEE Main 2026 (Online) 23rd January Evening Shift
8

The number of elements in the set S = \x : x [0, 100] and 0x t2 (x - t) dt = x2 \ is

JEE Main 2026 (Online) 23rd January Evening Shift
9

The value of - 2 2 ( 1[x] + 4 ) dx, where [ ] denotes the greatest integer function, is

  1. 160(21 - 1)
  2. 160( - 7)
  3. 760( - 3)
  4. 760(3 - 1)
JEE Main 2026 (Online) 22nd January Morning Shift
10

If ( x) -112( x) -52 dx = - p1q1( x) 92 - p2q2( x) 52 - p3q3( x) 12 + p4q4( x) -32 + C, where pi and qi are positive integers with (pi, qi) = 1 for i = 1, 2, 3, 4 and C is the constant of integration, then 15p1p2p3p4q1q2q3q4 is equal to

JEE Main 2026 (Online) 22nd January Morning Shift
11

Let [.] be the greatest integer function. If = 064 (x1/3 - [x1/3] )dx, then 1 0 ( 2 6 + 6 )d is equal to .

JEE Main 2026 (Online) 22nd January Evening Shift

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