When 0.1 mol MnO42- is oxidised the quantity of electricity required to completely oxidise MnO42- to MnO4- is
- 96500 C
- 2 96500 C
- 9650 C
- 96.50 C
Answer
(3) 9650 C
Solution
MnO42- MnO4- + e- (Mn: +6 +7)
⇒ 1 mol MnO42- needs 1 F = 96500 C
∴ For 0.1 mol: Q = 0.1 96500 = 9650 C
Answer: (3)