A solution contains Fe2+, Fe3+ and I- ions. This solution was treated with iodine at 35 C. E for Fe3+/Fe2+ is +0.77 V and E for I2/2I- = 0.536 V. The favourable redox reaction is
- I2 will be reduced to I-
- there will be no redox reaction
- I- will be oxidised to I2
- Fe2+ will be oxidised to Fe3+
Answer
(3) I- will be oxidised to I2
Solution
∵ E Fe3+/Fe2+ (0.77 V) > E I2/I- (0.536 V)
⇒ Fe3+ is the stronger oxidising agent and I- the stronger reducing agent.
2Fe3+ + 2I- 2Fe2+ + I2
E cell = 0.77 - 0.536 = +0.234 V (positive ⇒ spontaneous)
The reverse change (I2 oxidising Fe2+) has E cell = -0.234 V, so it is not favourable.
∴ I- will be oxidised to I2.
Answer: (3)