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Complex Numbers and Quadratic Equations · Question 24

JEE Main 2026 (Online) 24th January Evening ShiftNumericalEasy📈 Topic in 13% papers+4
1

Let z = (1 + i)(1 + 2i)(1 + 3i) (1 + ni), where i = -1. If |z|2 = 44200, then n is equal to .

Answer

5

Solution

|z|2 = |1 + i|2 |1 + 2i|2 |1 + ni|2

= (1 + 12)(1 + 22)(1 + 32) (1 + n2)

= 2 5 10 17 26

Products: 2, 10, 100, 1700, 44200

|z|2 = 44200 for n = 5

Answer: 5

JEE Main 2026 (Online) 24th January Evening Shift

Keep practising — Complex Numbers and Quadratic Equations

2

If α and β (α < β) are the roots of the equation (-2 + 3 ) ( | x - 3 | ) + (x - 6 x ) + (9 - 2 3 ) = 0, x 0, then + is equal to :

  1. 8
  2. 10
  3. 9
  4. 11
JEE Main 2026 (Online) 23rd January Morning Shift
3

Let S = \z : 3 |2z - 3(1 + i)| 7 \ be a set of complex numbers. Then Minz S | (z + 12(5 + 3i) ) | is equal to :

  1. 12
  2. 52
  3. 2
  4. 32
JEE Main 2026 (Online) 23rd January Morning Shift
4

A building construction work can be completed by two masons A and B together in 22.5 days. Mason A alone can complete the construction work in 24 days less than mason B alone. Then mason A alone will complete the construction work in :

  1. 36 days
  2. 24 days
  3. 30 days
  4. 42 days
JEE Main 2026 (Online) 23rd January Morning Shift
5

If z = 32 + i2, i = -1, then (z201 - i )8 is equal to

  1. 1
  2. 0
  3. -1
  4. 256
JEE Main 2026 (Online) 23rd January Evening Shift
6

The number of distinct real solutions of the equation x|x+4| + 3|x+2| + 10 = 0 is

  1. 2
  2. 3
  3. 0
  4. 1
JEE Main 2026 (Online) 22nd January Morning Shift
7

Let = -1 + i 32 and = -1 - i 32, i = -1. If (7 - 7 + 9 )20 + (9 + 7 - 7 )20 + (-7 + 9 + 7 )20 + (14 + 7 + 7 )20 = m10, then m is

JEE Main 2026 (Online) 22nd January Morning Shift
8

Let , be the roots of the quadratic equation 12x2 - 20x + 3 = 0, Z. If 12 | - | 32, then the sum of all possible values of is :

  1. 3
  2. 6
  3. 1
  4. 4
JEE Main 2026 (Online) 22nd January Evening Shift
9

Let S = \z C : 4z2 + z = 0\. Then z S |z|2 is equal to:

  1. 564
  2. 116
  3. 764
  4. 316
JEE Main 2026 (Online) 22nd January Evening Shift
10

If x2 + x + 1 = 0, then the value of (x + 1x )4 + (x2 + 1x2 )4 + (x3 + 1x3 )4 + + (x25 + 1x25 )4 is:

  1. 162
  2. 145
  3. 128
  4. 175
JEE Main 2026 (Online) 21st January Morning Shift
11

The sum of all the roots of the equation (x - 1)2 - 5|x - 1| + 6 = 0, is :

  1. 3
  2. 1
  3. 4
  4. 5
JEE Main 2026 (Online) 21st January Morning Shift

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