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If α and β (α < β) are the roots of the equation (-2 + 3 ) ( | x - 3 | ) + (x - 6 x ) + (9 - 2 3 ) = 0, x 0, then + is equal to :
(2) 10
x - 6 x + 9 = ( x - 3 )2, put t = | x - 3 | 0:
t2 + ( 3 - 2 )t - 2 3 = 0
(t - 2) (t + 3 ) = 0
t = 2 ( t 0)
x - 3 = 2 x = 5 or 1
x = 25 or 1 = 1, = 25
+ = 25 + 25 = 10
Answer: (2)
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