Two stationary sources each emit waves of wavelength . An observer moves from one source to the other with velocity u. Then the number of beats heard by him is
- 2u
- u
- u
- u2
Answer
(1) 2u
Solution
Let v be the speed of sound; frequency of each source = v
Observer approaching one source: 1 = v + uv
Observer receding from the other source: 2 = v - uv
Beats per second = 1 - 2
= 2uv
= v 2uv = 2u
Answer: (1)