For a travelling harmonic wave y(x, t) = 2.0 2 (10t - 0.0080x + 0.35), where x and y are in cm and t in s. The phase difference between oscillatory motion of two points separated by a distance of 0.5 m is:
- 0.08 π rad
- 0.008 π rad
- 0.8 π rad
- 8 π rad
Answer
(3) 0.8 π rad
Solution
Comparing with y = a ( t - kx + 0):
k = 2 0.0080 rad cm-1
x = 0.5 m = 50 cm
= k x = 2 0.0080 50
= 0.8 rad
Answer: (3)