For sound waves, if the number of nodes for the 5th harmonic of an open-ended pipe is n and that for the 9th harmonic of the same pipe with one of its ends closed is m, the ratio nm is
- 35
- 59
- 95
- 1
Answer
(4) 1
Solution
For an open-ended pipe:
The Nth harmonic has N nodes.
For the 5th harmonic, n = 5.
For a pipe with one end closed:
Only odd harmonics exist (1st, 3rd, 5th, 7th, 9th, ).
The frequency of the (2k - 1)th harmonic has k nodes.
For the 9th harmonic, 2k - 1 = 9 k = 5, so m = 5.
Therefore, the ratio is:
nm = 55 = 1
Answer: (4)