In a guitar, two strings A and B made of same material are slightly out of tune and produce beats of frequency 6 Hz. When tension in B is slightly decreased, the beat frequency increases. If the frequency of A is 530 Hz, the original frequency of B will be :
- 524 Hz
- 536 Hz
- 537 Hz
- 523 Hz
Answer
(1) 524 Hz
Solution
Beat frequency = |fA - fB| = 6 Hz
fB = 530 6 = 524 Hz or 536 Hz
f = 12l T , decreasing the tension in B decreases fB.
If fB = 536 Hz, a decrease in fB would bring it closer to 530 Hz and the beat frequency would decrease.
If fB = 524 Hz, a decrease in fB takes it further from 530 Hz and the beat frequency increases.
Original frequency of B = 524 Hz
Answer: (1)