A coil of 200 turns and area 0.20 m2 is rotated at half a revolution per second and is placed in uniform magnetic field of 0.01 T perpendicular to axis of rotation of the coil. The maximum voltage generated in the coil is 2 volt. The value of is .
Answer
5
Solution
=NBA t =- d dt=NBA t
=2 f=2 12= rad/s
max=NBA =200 0.01 0.20
=0.4 = 2 5 V =5
Answer: 5