A rectangular loop of sides 12 cm and 5 cm, with its sides parallel to the x-axis and y-axis respectively, moves with a velocity of 5 cm/s in the positive x axis direction, in a space containing a variable magnetic field in the positive z direction. The field has a gradient of 10-3 T/cm along the negative x direction and it is decreasing with time at the rate of 10-3 T/s. If the resistance of the loop is 6 m , the power dissipated by the loop as heat is 10-9 W.
Answer
216
Solution
[figure]
dBdx = -10-3 T/cm = -0.1 T/m B1 - B2 = 0.1 0.12 = 0.012 T
Motion (only the 5 cm sides cut field lines):
1 = (B1 - B2) v = 0.012 0.05 0.05 = 3 10-5 V
Time change: 2 = A | dBdt | = (60 10-4)(10-3) = 0.6 10-5 V
both decrease the flux through the loop ⇒ they add: = 3.6 10-5 V
P = 2R = (3.6 10-5)26 10-3
= 216 10-9 W
Answer: 216