A coil of self-inductance L is connected in series with a bulb B and an AC source. Brightness of the bulb decreases when
- a capacitance of reactance XC = XL is included in the same circuit.
- an iron rod is inserted in the coil.
- frequency of the AC source is decreased.
- number of turns in the coil is reduced.
Answer
(2) an iron rod is inserted in the coil.
Solution
Current I = V R2 + XL2 with XL = L
(1) XC = XL ⇒ resonance, Z = R ⇒ current increases, bulb brighter
(2) Iron rod inserted ⇒ L increases ⇒ XL increases ⇒ current decreases, bulb dimmer ✓
(3) Frequency decreased ⇒ XL decreases ⇒ bulb brighter
(4) Fewer turns ⇒ L decreases ⇒ bulb brighter
Answer: (2)