A resistance 'R' draws power 'P' when connected to an AC source. If an inductance is now placed in series with the resistance, such that the impedance of the circuit becomes 'Z', the power drawn will be
- P ( RZ )
- P
- P ( RZ )2
- P RZ
Answer
(3) P ( RZ )2
Solution
Without the inductor: P = V2R
With the inductor: I = VZ
P' = I2 R = V2 RZ2
= V2R R2Z2
P' = P ( RZ )2
Answer: (3)