A transformer having efficiency of 90% is working on 200 V and 3 kW power supply. If the current in the secondary coil is 6 A, the voltage across the secondary coil and the current in the primary coil respectively are
- 300 V, 15 A
- 450 V, 15 A
- 450 V, 13.5 A
- 600 V, 15 A
Answer
(2) 450 V, 15 A
Solution
Current in primary:
Ip = PinVp = 3000200 = 15 A
Output power:
Pout = 0.9 3000 = 2700 W
Vs = PoutIs = 27006 = 450 V
Answer: (2)