Let us consider a reversible reaction at temperature, T. In this reaction, both H and S were observed to have positive values. If the equilibrium temperature is Te, then the reaction becomes spontaneous at:
- Te > T
- T > Te
- T = Te
- Te = 5T
Answer
(2) T > Te
Solution
G = H - T S
At equilibrium, G = 0 Te = H S
For spontaneity, G < 0 T S > H
S > 0, T > H S = Te
Answer: (2)