Match List I with List II Choose the correct answer from the options given below:
- A-III, B-IV, C-II, D-I
- A-IV, B-III, C-I, D-II
- A-III, B-IV, C-I, D-II
- A-IV, B-III, C-II, D-I
Answer
(2) A-IV, B-III, C-I, D-II
Solution
A: glucose and galactose ( C6H12O6) differ only in configuration at C-4 ⇒ A-IV (epimers)
B: - and -glucose differ only at C-1 (anomeric carbon) ⇒ B-III (anomers)
C: glucose (aldohexose, –CHO) and fructose (ketohexose, >C=O), both C6H12O6 ⇒ C-I (functional isomers)
D: glucose C6H12O6 and ribose C5H10O5, both aldoses, differ by one CHOH unit ⇒ D-II (homologous)
∴ A-IV, B-III, C-I, D-II
Answer: (2)