In Carius method, 0.75 g of an organic compound gave 1.2 g of barium sulphate, find percentage of sulphur (molar mass 32 g mol-1). Molar mass of barium sulphate is 233 g mol-1.
- 4.55%
- 16.48%
- 10.30%
- 21.97%
Answer
(4) 21.97%
Solution
233 g of BaSO4 contains 32 g of S.
Mass of S in 1.2 g of BaSO4 = 32 1.2233 g
Percentage of S = 32 1.2 100233 0.75
% S = 3840174.75 = 21.97\%
Answer: (4)