Photons with energy 5 eV are incident on a cathode C in a photoelectric cell. The maximum energy of emitted photoelectrons is 2 eV. When photons of energy 6 eV are incident on C, no photoelectrons will reach the anode A, if the stopping potential of A relative to C is
- +3 V
- +4 V
- -1 V
- -3 V
Answer
(4) -3 V
Solution
Work function: 0 = 5 - 2 = 3 eV
With 6 eV photons: Kmax = 6 - 3 = 3 eV
Stopping potential V0 = 3 V, and the anode must be negative with respect to the cathode.
Potential of A relative to C = -3 V
Answer: (4)