If the kinetic energy of the particle is increased to 16 times its previous value, the percentage change in the de Broglie wavelength of the particle is
- 25
- 75
- 60
- 50
Answer
(2) 75
Solution
= h 2mK ⇒ 1 K
K' = 16K ⇒ ' = 4
Percentage change = - /4 100 = 75\% (decrease)
Answer: (2)