A source of light is placed at a distance of 50 cm from a photo cell and the stopping potential is found to be V0. If the distance between the light source and photo cell is made 25 cm, the new stopping potential will be :
- V0/2
- V0
- 4V0
- 2V0
Answer
(2) V0
Solution
Bringing the source closer only increases the intensity (number of photons).
∵ eV0 = h - 0 depends only on frequency, not on intensity
∴ The stopping potential stays V0 (only the photocurrent increases).
Answer: (2)