When a metallic surface is illuminated with radiation of wavelength , the stopping potential is V. If the same surface is illuminated with radiation of wavelength 2 , the stopping potential is V4. The threshold wavelength for the metallic surface is
- 52
- 3
- 4
- 5
Answer
(2) 3
Solution
Einstein's equation: eV0 = hc - hc 0
eV = hc - hc 0 ...(i)
eV4 = hc2 - hc 0 ...(ii)
Multiplying (ii) by 4 and equating with (i):
hc - hc 0 = 2hc - 4hc 0
3 0 = 1
0 = 3
Answer: (2)