Equilibrium

JEE Main 2024 (Online) 30th January Evening ShiftNumericalEasy📈 Topic in 14% papers+4

Ques. 1JEE Main 2024, 30 January (Evening Shift)

The pH of an aqueous solution containing 1 M benzoic acid (pKa = 4.20) and 1 M sodium benzoate is 4.5. The volume of benzoic acid solution in 300 mL of this buffer solution is mL. (given : log 2 = 0.3)

Answer

100

Solution

Acidic buffer (Henderson equation): pH = pKa + log [salt][acid]

Both solutions are 1 M ⇒ [salt][acid] = VsVa

4.5 = 4.2 + log VsVa ⇒ log VsVa = 0.3 = log 2 ⇒ Vs = 2Va

Va + Vs = 300 mL ⇒ 3Va = 300 mL

∴ Va = 100 mL

Answer: 100

Keep practising — Equilibrium

Ques. 2JEE Main 2024, 29 January (Morning Shift)

For the reaction N2O4(g) 2NO2(g), Kp = 0.492 atm at 300 K. Kc for the reaction at same temperature is 10-2. (Given : R = 0.082 L atm mol-1 K-1)

Ques. 3JEE Main 2024, 29 January (Evening Shift)

The following concentrations were observed at 500 K for the formation of NH3 from N2 and H2. At equilibrium ; [N2] = 2 10-2 M, [H2] = 3 10-2 M and [NH3] = 1.5 10-2 M. Equilibrium constant for the reaction is .

Ques. 4JEE Main 2024, 27 January (Morning Shift)

Given below are two statements : In the light of the above statements, choose the most appropriate answer from the options given below :

Both Statement I and Statement II are correct
Statement I is correct but Statement II is incorrect
Both Statement I and Statement II are incorrect
Statement I is incorrect but Statement II is correct

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