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d- and f-Block Elements · Question 1

JEE Advanced 2025 Paper 1MCQEasy📈 Topic in 17% papers+4−1
1

One of the products formed from the reaction of permanganate ion with iodide ion in neutral aqueous medium is

  1. I2
  2. IO3-
  3. IO4-
  4. IO2-

Answer

(2) IO3-

Solution

In neutral/faintly alkaline medium MnO4- is reduced to MnO2 and iodide is oxidised to iodate.

2MnO4- + H2O + I- 2MnO2 + 2OH- + IO3-

(In acidic medium the product would be I2.)

Answer: (B)

JEE Advanced 2025 Paper 1

Keep practising — d- and f-Block Elements

2

The pair(s) of diamagnetic ions is(are)

  1. La3+, Ce4+
  2. Yb2+, Lu3+
  3. La2+, Ce3+
  4. Yb3+, Lu2+
JEE Advanced 2025 Paper 1
3

The number of moles of potassium iodide required to produce two moles of P is .

JEE Advanced 2024 Paper 2
4

The number of zinc ions present in the molecular formula of Q is .

JEE Advanced 2024 Paper 2

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