1
The number of zinc ions present in the molecular formula of Q is .
Answer
3
Solution
P = K4[Fe(CN)6]. With ZnCl2 in slightly acidic medium it forms the sparingly soluble double salt potassium zinc ferrocyanide:
2K4[Fe(CN)6] + 3ZnCl2 K2Zn3[Fe(CN)6]2 + 6KCl
Q = K2Zn3[Fe(CN)6]2 3 zinc ions.
Answer: 3
JEE Advanced 2024 Paper 2