Consider the following processes : array|l|c| & H (kJ/mol) \ 12A B & +150 \ 3B 2C + D & -125 \ E + A 2D & +350 \ array For B + D E + 2C, H will be
- 525 kJ/mol
- -175 kJ/mol
- -325 kJ/mol
- 325 kJ/mol
Answer
(2) -175 kJ/mol
Solution
Using Hess's law, combine the given equations to get B + D E + 2C.
Multiply (i) by 2: A 2B ; H = +300 kJ/mol
Reverse (iii): 2D E + A ; H = -350 kJ/mol
Take (ii) as such: 3B 2C + D ; H = -125 kJ/mol
Adding: A + 2D + 3B 2B + E + A + 2C + D
⇒ B + D E + 2C
H = 300 - 350 - 125
= -175 kJ/mol
Answer: (2)