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One mole of an ideal diatomic gas undergoes a transition from A to B along a path AB as shown in the figure. [figure] The change in internal energy of the gas during the transition is
(4) -20 kJ
For a diatomic gas, Cv = 52R.
U = nCv T = 52nR(TB - TA) = 52(PBVB - PAVA)
= 52(2 6 - 5 4) kJ
= 52 (-8) kJ = -20 kJ
Answer: (4)
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