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Principles Related to Practical Chemistry · Question 10

JEE Main 2026 (Online) 4th April Morning ShiftNumericalMedium📈 Topic in 65% papers+4
1

2.0 g of a bromo hydrocarbon (X) was subjected to Carius analysis, gave 3.36 g of AgBr. The percentage of carbon in the compound (X) is 26.7%. Total number of carbon atoms in the empirical formula for compound (X) is . (Given molar mass in g mol-1 H : 1, C : 12, Br : 80, Ag : 108)

Answer

5

Solution

Molar mass of AgBr = 108 + 80 = 188 g mol-1

% Br = 80188 3.362.0 100 = 71.5\%

X contains only C, H and Br ⇒ % H = 100 − 26.7 − 71.5 = 1.8%

Atom ratio C : H : Br = 26.712 : 1.81 : 71.580

= 2.225 : 1.8 : 0.894

Dividing by 0.894 ⇒ 2.49 : 2.01 : 1 ≈ 2.5 : 2 : 1

Multiplying by 2 ⇒ 5 : 4 : 2 ⇒ empirical formula C5H4Br2

∴ Number of C atoms = 5

Answer: 5

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2

Among Fe3+, Pb2+, Cu2+ and Mn2+, identify the one that gets precipitated out while passing H2S in presence of NH4OH as group reagent. The highest possible oxidation state of the corresponding metal is

  1. +3
  2. +4
  3. +2
  4. +7
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3

Match the LIST-I with LIST-II Choose the correct answer from the options given below:

  1. A-III, B-I, C-IV, D-II
  2. A-III, B-IV, C-I, D-II
  3. A-I, B-III, C-II, D-IV
  4. A-I, B-II, C-III, D-IV
JEE Main 2026 (Online) 4th April Evening Shift
4

In sulphur estimation, 2.0 10-3 mol of an organic compound (X) (molar mass 76 g mol-1) gave 0.4813 g of barium sulphate (molar mass 233 g mol-1). The percentage of sulphur in the compound (X) is 10-1 % (Nearest integer)

JEE Main 2026 (Online) 4th April Evening Shift
5

Given below are two statements : In the light of the above statements, choose the correct answer from the options given below :

  1. Both Statement I and Statement II are true
  2. Both Statement I and Statement II are false
  3. Statement I is true but Statement II is false
  4. Statement I is false but Statement II is true
JEE Main 2026 (Online) 2nd April Morning Shift
6

Match List - I with List - II.

  1. A-IV, B-II, C-I, D-III
  2. A-IV, B-II, C-III, D-I
  3. A-II, B-IV, C-I, D-III
  4. A-II, B-IV, C-III, D-I
JEE Main 2026 (Online) 2nd April Morning Shift
7

A salt with few drops of conc. HCl gives apple green colour in flame test. The group precipitate of the salt is dissolved in acetic acid and treated with K2CrO4 to give yellow precipitate. When the sodium carbonate extract of the salt solution is heated with conc. HNO3 and ammonium molybdate, it resulted a canary yellow precipitate. The cation and anion present in the salt are respectively,

  1. Ca2+ and SO42-
  2. Ba2+ and PO43-
  3. Mn2+ and PO43-
  4. Ba2+ and SO42-
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8

Complete combustion of X g of an organic compound gave 0.25 g of CO2 and 0.12 g of H2O. If the % of carbon is 25% and of hydrogen is 4.89%, then X = 10-3 g. (Nearest integer) (Molar mass of C, H and O are 12, 1 and 16 g mol-1 respectively.)

  1. 273
  2. 27
  3. 2730
  4. 227
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9

Method used for separation of mixture of products (B and C) obtained in the following reaction is [figure]

  1. simple distillation
  2. sublimation
  3. fractional distillation
  4. steam distillation
JEE Main 2026 (Online) 28th January Morning Shift
10

Given below are two statements: In the light of the above statements, choose the correct answer from the options given below

  1. Statement I is true but Statement II is false
  2. Both Statement I and Statement II are false
  3. Statement I is false but Statement II is true
  4. Both Statement I and Statement II are true
JEE Main 2026 (Online) 28th January Morning Shift
11

0.53 g of an organic compound (x) when heated with excess of nitric acid (concentrated) and then with silver nitrate gave 0.75 g of silver bromide precipitate. 1.0 g of (x) gave 1.32 g of CO2 gas on combustion. The percentage of hydrogen in the compound (x) is %. [Nearest Integer] [Given: Molar mass in g mol-1 H : 1, C : 12, Br : 80, Ag : 108, O : 16; Compound (x) : CxHyBrz]

JEE Main 2026 (Online) 28th January Morning Shift

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