The magnetic field at the centre of a current carrying circular loop of radius R is 16 . The magnetic field at a distance x = 3R on its axis from the centre is .
- 8
- 2
- 4
- 2 2
Answer
(2) 2
Solution
Field at the centre: B0 = 0 I2R
Field on the axis: B = 0 I R22(R2 + x2)3/2
BB0 = R3(R2 + x2)3/2
With x = 3R: R2 + x2 = 4R2
BB0 = R3(4R2)3/2 = R38R3 = 18
B = 168 = 2
Answer: (2)