The current passing through a conducting loop in the form of equilateral triangle of side 4 3 cm is 2 A. The magnetic field at its centroid is 10-5 T. The value of is . (Given: 0 = 4 10-7 SI units)
- 3 3
- 2 3
- 3
- 32
Answer
(1) 3 3
Solution
Distance of the centroid from each side: d = a2 3 = 4 32 3 = 2 cm = 0.02 m
Each side subtends 60 on either side of the perpendicular:
Bside = 0 I4 d( 60 + 60 ) = 10-7 20.02 3 = 3 10-5 T
All three sides give fields in the same direction:
B = 3 3 10-5 = 3 3 10-5 T = 3 3
Answer: (1)