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p-Block Elements (Group 15–18) · Question 6

JEE Advanced 2025 Paper 2Multiple CorrectEasy📈 Topic in 17% papers+4−1
1

The compound(s) with P–H bond(s) is(are)

  1. H3PO4
  2. H3PO3
  3. H4P2O7
  4. H3PO2

Answer

(2) H3PO3, (4) H3PO2

Solution

Count P–OH (ionisable H) vs P–H bonds from structures.

H3PO4: O=P(OH)3 — no P–H.

H3PO3: O=PH(OH)2 — one P–H (dibasic).

H4P2O7: (HO)2P(O)-O-P(O)(OH)2 — no P–H.

H3PO2: O=PH2(OH) — two P–H (monobasic).

Answer: (B), (D)

JEE Advanced 2025 Paper 2

Keep practising — p-Block Elements (Group 15–18)

2

At room temperature, disproportionation of an aqueous solution of in situ generated nitrous acid (HNO2) gives the species

  1. H3O+, NO3- and NO
  2. H3O+, NO3- and NO2
  3. H3O+, NO- and NO2
  4. H3O+, NO3- and N2O
JEE Advanced 2024 Paper 1
3

Based on VSEPR model, match the xenon compounds given in List-I with the corresponding geometries and the number of lone pairs on xenon given in List-II and choose the correct option.

  1. P-5, Q-2, R-3, S-1
  2. P-5, Q-3, R-2, S-4
  3. P-4, Q-3, R-2, S-1
  4. P-4, Q-2, R-5, S-3
JEE Advanced 2024 Paper 1
4

The species formed on fluorination of phosphorus pentachloride in a polar organic solvent are

  1. [PF4]+[PF6]- and [PCl4]+[PF6]-
  2. [PCl4]+[PCl4F2]- and [PCl4]+[PF6]-
  3. PF3 and PCl3
  4. PF5 and PCl3
JEE Advanced 2024 Paper 2
5

The compound(s) having peroxide linkage is(are)

  1. H2S2O7
  2. H2S2O8
  3. H2S2O5
  4. H2SO5
JEE Advanced 2024 Paper 2

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