An insulated wire is wound so that it forms a flat coil with N=200 turns. The radius of the innermost turn is r1=3 cm, and of the outermost turn r2=6 cm. If 20 mA current flows in it then the magnetic moment will be 10-2 A m2. The value of is .
- 4.4
- 2.64
- 3.25
- 1.2
Answer
(2) 2.64
Solution
[figure]
Turns are spread uniformly from r1 to r2: number of turns per unit radial width = Nr2-r1
A ring of radius r and width dr has N drr2-r1 turns, each of area r2:
dm=I N drr2-r1 r2
⇒ m= NIr2-r1 r1r2r2 dr= NI (r23-r13)3(r2-r1)
r23-r13=(216-27) 10-6=189 10-6 m3, r2-r1=0.03 m
⇒ m= 200 0.02 189 10-63 0.03=8.4 10-3 A m2
⇒ m 2.64 10-2 A m2
∴ =2.64
Answer: (2)