1 μC charge moving with velocity v= ( i-2 j+3 k ) m/s in the region of magnetic field B= (2 i+3 j-5 k ) T. The magnitude of force acting on it is 10-6 N. The value of is .
Answer
171
Solution
F=q( v B)
v B= vmatrix i& j& k\\1&-2&3\\2&3&-5 vmatrix
= i(10-9)- j(-5-6)+ k(3+4)
= i+11 j+7 k
| v B|= 1+121+49= 171
| F|=10-6 171 N
=171
Answer: 171