An electron of mass m and a photon have same energy E. The ratio of de-Broglie wavelengths associated with them is
- c(2mE) 12
- 1c ( 2mE ) 12
- 1c ( E2m ) 12
- ( E2m ) 12
Answer
(3) 1c ( E2m ) 12
Solution
Electron: p = 2mE e = h 2mE
Photon: E = hc p p = hcE
e p = h 2mE Ehc
= 1c E2m = 1c ( E2m ) 12
Answer: (3)