Oxidation states of P in H4P2O5, H4P2O6, H4P2O7 are respectively
- +3, +5, +4
- +5, +3, +4
- +5, +4, +3
- +3, +4, +5
Answer
(4) +3, +4, +5
Solution
Let the oxidation state of P be x (H = +1, O = −2).
H4P2O5: 4 + 2x - 10 = 0 x = +3
H4P2O6: 4 + 2x - 12 = 0 x = +4
H4P2O7: 4 + 2x - 14 = 0 x = +5
+3, +4, +5
Answer: (4)