If an iron (III) complex with the formula [Fe(NH3)x(CN)y]- has no electron in its eg orbital, then the value of x + y is
- 6
- 4
- 3
- 5
Answer
(1) 6
Solution
Fe3+: 3d5; no electron in eg ⇒ t2g5eg0 (low spin, strong field CN-) ⇒ octahedral, d2sp3
∴ coordination number = x + y = 6
Charge balance: +3 + 0(x) + (-1)y = -1 ⇒ y = 4, x = 2
⇒ complex is [Fe(NH3)2(CN)4]-
Answer: (1)