A real gas within a closed chamber at 27 undergoes the cyclic process as shown in figure. The gas obeys PV3 = RT equation for the path A to B. The net work done in the complete cycle is (assuming R = 8 J/mol K): [figure]
- -20 J
- 205 J
- 225 J
- 20 J
Answer
(2) 205 J
Solution
A B (PV3 = RT, T = 300 K): WAB = 24 RTV3 dV = RT2 ( 122 - 142 )
= 8 3002 316 = 225 J
B C (isobaric):
WBC = P(VC - VB) = 10(2 - 4) = -20 J
C A (isochoric): WCA = 0
Wnet = 225 - 20 + 0 = 205 J
Answer: (2)