The heat absorbed by a system in going through the given cyclic process is : [figure]
- 61.6 J
- 431.2 J
- 19.6 J
- 616 J
Answer
(1) 61.6 J
Solution
Cyclic process: U = 0
Q = W = area of the circle (W > 0, clockwise cycle)
Radius = 140 kPa along P and 140 cc along V
W = (140 103 Pa) (140 10-6 m3)
= 19.6 61.6 J
Answer: (1)