An electric heater supplies heat to a system at a rate of 100 W. If the system performs work at a rate of 75 J/s, then the rate at which internal energy increases will be :
- 75 W
- 25 W
- 100 W
- 125 W
Answer
(2) 25 W
Solution
By the first law of thermodynamics, Q = U + W
dQdt = dUdt + dWdt
dUdt = dQdt - dWdt = 100 - 75
dUdt = 25 J/s = 25 W
Answer: (2)