An aqueous solution of HCl with pH 1.0 is diluted by adding equal volume of water (ignoring dissociation of water). The pH of HCl solution would (Given 2 = 0.30)
- increase to 1.3
- reduce to 0.5
- increase to 2
- remain same
Answer
(1) increase to 1.3
Solution
pH = 1.0 [H+] = 10-1 M = 0.1 M
An equal volume of water doubles the volume, the concentration is halved (M1V1 = M2V2):
[H+] = 0.12 = 5 10-2 M
pH = - (5 10-2)
= 2 - 5 = 2 - (1 - 2)
= 1 + 0.30 = 1.3
The pH increases from 1.0 to 1.3.
Answer: (1)