Phthalimide is made to undergo following sequence of reactions. [figure] Total number of bonds present in product 'P' is/are .
Answer
8
Solution
Gabriel phthalimide reaction: KOH forms the potassium salt; its N substitutes Cl of benzyl chloride (SN2).
[figure]
P = N-benzylphthalimide
π bonds: benzene ring of phthalimide = 3, two C=O = 2, benzyl ring = 3
∴ Total π bonds = 3 + 2 + 3 = 8
Answer: 8