From 6.55 g of aniline, the maximum amount of acetanilide that can be prepared will be 10-1 g.
Answer
95
Solution
C6H5NH2 (CH3CO)2O C6H5NHCOCH3 (1 : 1)
Molar mass: aniline = 93, acetanilide = 135 g mol-1
Mass of acetanilide = 6.5593 135
= 9.51 g 95 10-1 g
Answer: 95