Let A = bmatrix 2 & 2+p & 2+p+q \ 4 & 6+2p & 8+3p+2q \ 6 & 12+3p & 20+6p+3q bmatrix. If (adj(adj(3A))) = 2m 3n, m, n N, then m + n is equal to
- 22
- 20
- 24
- 26
Answer
(3) 24
Solution
C3 C3 - C2, C2 C2 - C1:
|A| = vmatrix 2 & p & q \ 4 & 2+2p & 2+p+2q \ 6 & 6+3p & 8+3p+3q vmatrix
R2 R2 - 2R1, R3 R3 - 3R1:
|A| = vmatrix 2 & p & q \ 0 & 2 & 2+p \ 0 & 6 & 8+3p vmatrix = 2[2(8+3p) - 6(2+p)] = 2 4 = 8
|3A| = 33 8 = 216 = 23 33
For a matrix B of order 3: |adj B| = |B|2 |adj(adj B)| = |B|4
(adj(adj(3A))) = 2164 = 212 312
m = n = 12 m + n = 24
Answer: (3)