The potential energy of a long spring when stretched by 2 cm is U. If the spring is stretched by 8 cm the potential energy stored in it is
- U/4
- 4U
- 8U
- 16U
Answer
(4) 16U
Solution
U = 12kx2 ⇒ U x2
U'U = ( 82 )2 = 16
∴ U' = 16U
Answer: (4)
The potential energy of a long spring when stretched by 2 cm is U. If the spring is stretched by 8 cm the potential energy stored in it is
(4) 16U
U = 12kx2 ⇒ U x2
U'U = ( 82 )2 = 16
∴ U' = 16U
Answer: (4)
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