A body of mass 3 kg is under a constant force which causes a displacement s in metres in it, given by the relation s = 13t2, where t is in seconds. Work done by the force in 2 seconds is
- 195 J
- 519 J
- 38 J
- 83 J
Answer
(4) 83 J
Solution
v = dsdt = 23t ⇒ at t = 0, v = 0; at t = 2 s, v = 43 m/s
By the work–energy theorem:
W = 12mv2 - 0 = 12 3 ( 43 )2
= 12 3 169 = 83 J
Answer: (4)