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Polymers · Question 3

JEE Advanced 2024 Paper 2NumericalHard📈 Topic in 17% papers+4
1

The molecular weight of U is .

Answer

93018

Solution

Monomers (from the previous question): [figure] (Q, M = 104) and [figure] (R, M = 118)

Each –OH of one hydroxy acid forms an ester with the –COOH of the next, losing H2O, e.g.

[figure] + [figure] -H2O [figure]

U is one linear polyester (PHBV type) of 1000 monomer units: an acyclic chain of 1000 units has 999 ester links, so 999 H2O are lost.

M(U) = 500 104 + 500 118 - 999 18

= 52000 + 59000 - 17982 = 93018

Answer: 93018

JEE Advanced 2024 Paper 2

Keep practising — Polymers

2

In the following reaction sequence, major products X and Y are acyclic monomers. CH3I [ 3. Red P, Br2\ 4. NH3 (excess)] 1. KCN\ 2. H3O+, X [figure] 500 mol of X completely reacts with 500 mol of Y to give 1 mol of a single biodegradable acyclic copolymer Z as the only product. The amount of Z formed in grams is . Given: Atomic mass (in amu): H : 1, C : 12, N : 14, O : 16, Br : 80

JEE Advanced 2026 Paper 2
3

The monomer (X) involved in the synthesis of Nylon 6,6 gives positive carbylamine test. If 10 moles of X are analyzed using Dumas method, the amount (in grams) of nitrogen gas evolved is . Use: Atomic mass of N (in amu) = 14

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